Slope of the tangent to the curve xy = 6 at (1,0)

1.	Slope of the tangent to the curve xy = 6 at (1,0)
Answer» Answer: We have, xy=6 Now, differentiate w.r.t X, we get y+xdxdy=0 xdxdy=−y dxdy=−xy Put x=1,y=6 So, dxdy(1,6)=−16 dxdy(1,6)=−6 Therefore, The SLOPE of the tangent of the curve =−6 And the slope of the NORMAL the curve =−m1 =−−61 =61

Answer»

Answer:

We have,

xy=6

Now, differentiate w.r.t X, we get

y+xdxdy=0

xdxdy=−y

dxdy=−xy

Put x=1,y=6

So,

dxdy(1,6)=−16

dxdy(1,6)=−6

Therefore,

The SLOPE of the tangent of the curve

=−6

And the slope of the NORMAL the curve

=−m1

=−−61

=61

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