InterviewSolution
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समीकरण `|(x+2,1,-3),(1,x-3,-2),(-3,-2,1)|=0` को हल कीजिए |
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Answer» `|(x+2,1,-3),(1,x-3,-2),(-3,-2,1)|=0` `implies|(x-2,1,-3),(-(x-2),x-3,-2),(0,-2,1)|=0` `C_(1)toC_(1)-C_(2)+C_(3)` से `implies(x-2)|(1,1,-3),(-1,x-3,-2),(0,-2,1)|=0` `implies(x-2)|(1,1,-3),(0,x-2,-5),(0,-2,1)|=0 R_(2)toR_(2)` से `implies(x-2).1|(x-2,-5),(-2,1)|=0` ( `C_(1)` से विस्तार करने पर) `implies(x-2)(x-2-10)=0` `implies(x-2)(x-12)=0` `impliesx=2` या `x=12` |
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