1.

समीकरण `|(x+2,1,-3),(1,x-3,-2),(-3,-2,1)|=0` को हल कीजिए

Answer» `|(x+2,1,-3),(1,x-3,-2),(-3,-2,1)|=0`
`implies|(x-2,1,-3),(-(x-2),x-3,-2),(0,-2,1)|=0`
`C_(1)toC_(1)-C_(2)+C_(3)` से
`implies(x-2)|(1,1,-3),(-1,x-3,-2),(0,-2,1)|=0`
`implies(x-2)|(1,1,-3),(0,x-2,-5),(0,-2,1)|=0 R_(2)toR_(2)` से
`implies(x-2).1|(x-2,-5),(-2,1)|=0`
( `C_(1)` से विस्तार करने पर)
`implies(x-2)(x-2-10)=0`
`implies(x-2)(x-12)=0`
`impliesx=2` या `x=12`


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