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समतलों `vecr.(2hati-3hatj+4hatk)=1` तथा `vecr.(-hati+hatj)=4` के बीच का कोण ज्ञात कीजिए।

Answer» Correct Answer - `cos^(-1)((5)/(sqrt(58)))`
`cos theta =|(a_(1)a_(2)+b_(1)b_(2)+c_(1)c_(2))/(sqrt(a_(1)^(2)+b_(1)^(1)+c_(1)^(2))*sqrt(a_(2)^(2)+b_(2)^(2)+c_(2)^(2)))|`


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