SnCl_(2) + HCl + I_(2) rarr A+ B. The compounds (A ) and (B ) are

1.	SnCl_(2) + HCl + I_(2) rarr A+ B. The compounds (A ) and (B ) are
Answer» `SnI_(2), Cl_(2)` `H_(2)SnCl_(4), HI` `SnCl_(4), HI` `HSnCl_(3), HI` Solution :`SnCl_(2) + 2HCL + I_(2) rarr SnCl_(4) + 2HI`

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