1.

Sodium has a bcc structure with nearest neighbour distance 365.9 pm. Calculate its density (Atomic mass of sodium =23)

Answer»

Solution :For the BCC structure , nearest NEIGHBOUR distance (d) is RELATED to the edge (a) as `d=sqrt3/2 a`
or `a=2/sqrt3 d =2/1.732xx365.9` =422.5 pm
For bcc structure, Z=2
For sodium , M=23 `THEREFORE RHO =(ZxxM)/(a^3xxN_0)=(2xx23 g mol^(-1))/((422.5xx10^(-10)cm)^3xx(6.02xx10^23 mol^(-1))=1.51 g//cm^3`


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