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Sodium has a bcc structure with nearest neighbour neighbour distance 365.9 pm. Calculate its density (Atomic mass of sodium = 23)

Answer»

Solution :For the BCC, structure, nearst NEIGHBOUR distance (d)is related to the edge (a) as ` d= sqrt3/2 a`
or ` a= 2/sqrt3 d = 2 / 1.732 xx 365.9 = 422.5` pm.
For bcc stucture, Z =2
For sodiumM= 23 , ` p = ( Z xx M)/ (a^(3) xx N_(0)) = (2xx23 "g mol"^(-1))/((422.5xx10^(-10) cm)^(3)xx(6.02xx 10^(23)"mol"^(-1)))= 1.51 "g/cm"^(3)`


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