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Sodium is there in a solution with 10 kg of solvent \( \left(\right. \) Density \( \left.=5 Kg / m ^{3}\right) \) and concentration 4 molar. 1) 23 grams 2) 92 grams 3) 184 grams 4) 276 grams |
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Answer» We have given, concentration of sodium solution = 4M density of solvent = 5kg/dm3 \(\therefore\) Volume of 10 Kg solvent = 10/5 m3 = 2m3 \(\because\) 1 dm3 = 1 L \(\therefore\) 2dm3 = 2 L as we know molarity = \(\cfrac{\frac{weight\,of\,solute}{molecule\,wt\,of\,solute}}{Volume of solution(L)}\) ⇒ 4 = \(\cfrac{\frac{w}{23}}{2L}\) ⇒ w = 4 x 2 x 23 w = 184 gram. |
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