Sodium lamps are used in foggy conditions becauseA. (a) yellow light is scattered more by the fog particlesB. (b) yellow light is unaffected during its passage through the fogC. (c) yellow light is scattered less by the fog particlesD. (d) wavelength of yellow light is the mean of the visible part of the spectrum

Sodium lamps are used in foggy conditions becauseA. (a) yellow light i

1.	Sodium lamps are used in foggy conditions becauseA. (a) yellow light is scattered more by the fog particlesB. (b) yellow light is unaffected during its passage through the fogC. (c) yellow light is scattered less by the fog particlesD. (d) wavelength of yellow light is the mean of the visible part of the spectrum
Answer» Correct Answer - C Sodium light emits monochromatic light which has only one colour (deep yellow). This colour is scattered less by the fog particles. While the other light sources comprise lights of many different colours (of different wavelengths) so they are scattered most due to they provide some degree of colour rendering.

Discussion

No Comment Found

Related InterviewSolutions

Angular width of central maxima in the Fraunhofer diffraction pattern of a slit is measured. The slit is illuminated by light of wavelength `6000Å`. When the slit is illuminated by light of another wavelength, the angular width decreases by 30%. The wavelength of this light will beA. `3500 Å`B. `4200 Å`C. `4700 Å`D. `6000 Å`
Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width `12xx10^(-5)cm` when the slit is illuminated by monochromatic light of wavelength 6000 Å.
Find the half angular width of the central bright maximum in the fraunhofer diffraction pattern of a slit of width `12xx10^(-5)cm` when the slit is illuminated by monochromatic light of wavelength 6000 Å.A. `40^(@)`B. `45^(@)`C. `30^(@)`D. `60^(@)`
In a single slit diffraction, the width of slits is `0.5cm`, focal length of lens is 40 cm and of first dark fringe is
What will be the angular width of central maxima in Fraunhofer diffraction when light of wavelength `6000Å` is used and slit width is `12xx10^-5cm`?A. (a) `2rad`B. (b) `3rad`C. (c) `1rad`D. (d) `8rad`
A light wave is incident normally over a slit of width `24xx10^-5cm`. The angular position of second dark fringe from the central maxima is `30^@`. What is the wavelength of light?A. `6000 Å`B. `5000 Å`C. `3000 Å`D. `1500 Å`
Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :A. `0.9^(@)`B. `0.18^(@)`C. `0.54^(@)`D. `0.36^(@)`
Light of wavelength `6328 Å` is incident normally on a slit of width 0.2 mm. Angular width of the central maximum on the screen will be :A. `0.36^(@)`B. `0.18^(@)`C. `0.72^(@)`D. `0.09^(@)`
Light wavelength 6000 Å is incident normally on a slit of width `24xx10^(-5)` cm. find out the angular position of seconds minimum from central maximum?A. `12 xx 10^(-5)cm`B. `18xx10^(-5)cm`C. `24xx10^(-5)cm`D. `36xx10^(-5)cm`
Light wavelength 6000 Å is incident normally on a slit of width `24xx10^(-5)` cm. find out the angular position of seconds minimum from central maximum?

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment