Solid A "and" B are taken in a closed container at a certain temperature. These two solids decompose are following equilibria are established simultaneously A(s)hArrX(g)+Y(g) K_(P_(1)=250atm^(2) B(s)hArrY(g)+Z(g) K_(P_(2)=? If the total pressure developed over the solid mixture is 50 atm. Then the value of K_(P) for the 2^(nd) reaction

Solid A "and" B are taken in a closed container at a certain temperatu

1.	Solid A "and" B are taken in a closed container at a certain temperature. These two solids decompose are following equilibria are established simultaneously A(s)hArrX(g)+Y(g) K_(P_(1)=250atm^(2) B(s)hArrY(g)+Z(g) K_(P_(2)=? If the total pressure developed over the solid mixture is 50 atm. Then the value of K_(P) for the 2^(nd) reaction
Answer» `375` `625` `225` `250` Solution :`A(s)X+Y` `alpha alpha+beta` `B(s)hArrY+Z` `beta+alpha beta` `rArrK_(P_(1)=alpha(alpha+beta)` `K_(P_2)=beta(alpha+beta)` `P_(total)=(alpha+beta)+alpha+beta=2(alpha+beta)` `RARR 2(alpha+beta)=50rArr alpha+beta=25` `rArr 250=25alpha rArr alpha=10,beta=15` `rArr K_(P_(2)=beta(alpha+beta)=15xx25=375`