Solid ammonium dichromate decomposes as the equationr: (NH44)2Cr2O7�

1.	Solid ammonium dichromate decomposes as the equationr: (NH44)2Cr2O7→N2+Cr2O3+4H2O If 63 g of sammonium dichromate decomposes, calculate: (a) the quantity in moles of (NH4)2Cr2O7 (b) the qunatity in moles of nitrogen formed (c) the volume of N2 evolved at STP (d) the loss of mass (e) the mass of chromium (iii) oxide formed at the same time.
Answer» Solid ammonium dichromate decomposes as the equationr: $(N H_{4} 4)_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O$ If 63 g of sammonium dichromate decomposes, calculate: (a) the quantity in moles of $(N H_{4})_{2} C r_{2} O_{7}$ (b) the qunatity in moles of nitrogen formed (c) the volume of $N_{2}$ evolved at STP (d) the loss of mass (e) the mass of chromium (iii) oxide formed at the same time.

Solid ammonium dichromate decomposes as the equationr: (NH44)2Cr2O7→N2+Cr2O3+4H2O If 63 g of sammonium dichromate decomposes, calculate: (a) the quantity in moles of (NH4)2Cr2O7 (b) the qunatity in moles of nitrogen formed (c) the volume of N2 evolved at STP (d) the loss of mass (e) the mass of chromium (iii) oxide formed at the same time.

Answer»

Solid ammonium dichromate decomposes as the equationr:

$(N H_{4} 4)_{2} C r_{2} O_{7} \to N_{2} + C r_{2} O_{3} + 4 H_{2} O$
If 63 g of sammonium dichromate decomposes, calculate:
(a) the quantity in moles of $(N H_{4})_{2} C r_{2} O_{7}$
(b) the qunatity in moles of nitrogen formed
(c) the volume of $N_{2}$ evolved at STP

(d) the loss of mass
(e) the mass of chromium (iii) oxide formed at the same time.

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