1.

Solubility of a sparingly soluble salt S , specific conductance K , and the equivalent conductance `Lambda_(0)` are related asA. `S = (1000 Lambda_(0))/(K)`B. `S = K Lambda_(0)`C. `S = (K)/(1000 Lambda_(0))`D. `S = (1000 K )/(Lambda_(0))`

Answer» Correct Answer - D
`Lambda = (k xx 1000)/("Molarity")` . For a sparingly soluble salt ,
`Lambda = Lambda_(0)` and Molarity = Solubility (S) .
Hence `S = (k xx 1000)/(Lambda_(0))`


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