Solubility of ammouium choride at 293k is 37g.what mass of ammouium ch

1.	Solubility of ammouium choride at 293k is 37g.what mass of ammouium choride would be needed to make saturated solution in 10g of water at 293k
Answer» Explanation: 3.7 gram of AMMONIUM Chloride WOULD be needed to make a SATURATED SOLUTION in 10 gram of water at 293 K Explanation: Solubility of Ammonium Chloride (NH₄Cl) at 293 K is 37 gram/100 mL ⇒ 37 gram of NH₄Cl is soluble in 100 mL of water or, 37 gram of NH₄Cl is soluble in 100 gram of water (∵ density of water = 1g/ml) ∵ In 100 gram of water AMOUNT of NH₄Cl soluble = 37 gram ∴ In 1 gram of water, amount of NH₄Cl soluble = 37/100 gram = 0.37 gram ∴ In 10 gram of water, amount of NH₄Cl soluble = 0.37 × 10 = 3.7 gram Therefore, 3.7 gram of Ammonium Chloride would be needed to make a saturated solution in 10 gram of water 5.0 5 votes Read more on Brainly.in - brainly.in/question/11716794#readmore

Solubility of ammouium choride at 293k is 37g.what mass of ammouium choride would be needed to make saturated solution in 10g of water at 293k

Answer»

Explanation:

3.7 gram of AMMONIUM Chloride WOULD be needed to make a SATURATED SOLUTION in 10 gram of water at 293 K

Explanation:

Solubility of Ammonium Chloride (NH₄Cl) at 293 K is 37 gram/100 mL

⇒ 37 gram of NH₄Cl is soluble in 100 mL of water

or, 37 gram of NH₄Cl is soluble in 100 gram of water

(∵ density of water = 1g/ml)

∵ In 100 gram of water AMOUNT of NH₄Cl soluble = 37 gram

∴ In 1 gram of water, amount of NH₄Cl soluble = 37/100 gram

= 0.37 gram

∴ In 10 gram of water, amount of NH₄Cl soluble = 0.37 × 10 = 3.7 gram

Therefore, 3.7 gram of Ammonium Chloride would be needed to make a saturated solution in 10 gram of water

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