InterviewSolution
Saved Bookmarks
| 1. |
Solubility of `BaF_(2)` in a solution of `Ba(NO_(3))_(2)`, will be represented by the concentration term:A. `[Ba^(2+)]`B. `[F^(-1)]^(2)`C. `(1)/(2)[F^(-1)]`D. `2[NO_(3)^(-)]` |
|
Answer» Correct Answer - C `Ba(NO_(3))_(2)` gives `Ba^(2+)` and `NO_(3)^(-)` ions, hence, concentration of `Ba^(2+)` ion increases. To keep `K_(sp)` constant, `[F^(-)]` decreases. Thus, it is represented as `(1)/(2)[F^(-)]` |
|