Solubility product of BaCO3 is 2.6×10–⁹ estimate it's solubility?

1.	Solubility product of BaCO3 is 2.6×10–⁹ estimate it's solubility?
Answer» TION:[CO32-] = 0.60 MAT equilibrium:BaCO3 <----> Ba2+ + CO32- s 0.6 + sKsp = [Ba2+][CO32-]2.610^-9=(s)(0.6+ s)Since Ksp is small, s can be ignored as compared to 0.6Above EXPRESSION thus becomes:2.610^-9=(s)(0.6)2.610^-9= (s) 0.6s = 4.33310^-9 MAnswer: 4.310^-9 Mplease MARK me as a brain list

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