InterviewSolution
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InterviewSolution
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solubility product of radium sulphate is `4xx10^(-9)`. What will be the solubility of ` Ra^(2+)` in ` 0.10 M` ` NaSO_(4)`?A. `xx10^(-10)M`B. `2xx10^(-5)M`C. `4xx10^(-5)M`D. `2xx10^(-10)M` |
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Answer» Correct Answer - A `RaSO_(4)hArrRa^(2+)+SO_(4)^(2-)` `K_(sp)=[Ra^(2+)][SO_(4)^(2-)]` Concentration of `SO_(4)^(2-)` from `Na_(2)SO_(4)=0.10M` `Ra^(2+)=(4xx10^(-11))/(0.10)=4xx10^(-10)` |
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