1.

Solubility products of ACO_(3), BSO_(4), and ASO_(4), are 4 xx 10^(-10), 6 xx 10^(-10) and 8 xx 10^(-10) respectively. The solubility product of BCO_(3), is x x 10^(-10), What is x ?

Answer»


Solution :` ([A^(+2) ][CO_3^(-2)] )/([A^(+2)][SO_4^(-2)])=(1)/(2),[SO_4^(-2) ] =2 [CO_3^(-2) ]`
` [B^(+2) ][SO_4^(-2) ] = 6 xx 10 ^(-10) `
` [B ^(+2) ] 2 [CO_3^(-2) ]=6 xx 10 ^(_10) `
` [B^(+2) ][CO_3^(-2) ]=3xx 10 ^(-10) `


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