1.

Solution containing 23 g HCOOH is/are :

Answer»

`46 g` of `70% ((w)/(v)) HCOOH (d_("SOLUTION") = 1.40 g//mL)`
`50 g` of `10 MHCOOH (d_("solution") = 1 g//mL)`
`50 g` of `25% ((w)/(w)) = HCOOH`
`46 g` of `5" " M" "HCOOH (d_("solution") = 1 g//mL)`

Solution :`(a)` In `100ML(140 g)` solution mass of SOLUTE
`= 70= (70)/(140)xx46=23 g`
`(b) 10M=("Mass of solute" //46)/((50)/(1xx1000))`
Mass of solute `=23 g`
`(c ) 100 g` solution contain `25 g` of solute mass of solute `=(25)/(100)xx50=12.5`
`(d) 5 M =("Mass of solute"//46)/(46//1000)`
Mass of solute `=10.58 g`


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