Saved Bookmarks
| 1. |
Solution containing 23 g HCOOH is/are : |
|
Answer» `46 g` of `70% ((w)/(v)) HCOOH (d_("SOLUTION") = 1.40 g//mL)` `= 70= (70)/(140)xx46=23 g` `(b) 10M=("Mass of solute" //46)/((50)/(1xx1000))` Mass of solute `=23 g` `(c ) 100 g` solution contain `25 g` of solute mass of solute `=(25)/(100)xx50=12.5` `(d) 5 M =("Mass of solute"//46)/(46//1000)` Mass of solute `=10.58 g` |
|