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Solution containing `23 g HCOOH` is/are :A. `46 g` of `70% ((w)/(v)) HCOOH (d_("solution") = 1.40 g//mL)`B. `50 g` of `10 M HCOOH (d_("solution") = 1 g//mL)`C. `50 g` of `25% ((w)/(w)) = HCOOH`D. `46 g` of `5" " M" "HCOOH (d_("solution") = 1 g//mL)` |
Answer» Correct Answer - A::B `(a)` In `100mL(140 g)` solution mass of solute `= 70= (70)/(140)xx46=23 g` `(b) 10M=("Mass of solute" //46)/((50)/(1xx1000))` Mass of solute `=23 g` `(c ) 100 g` solution contain `25 g` of solute mass of solute `=(25)/(100)xx50=12.5` `(d) 5 M =("Mass of solute"//46)/(46//1000)` Mass of solute `=10.58 g` |
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