1.

Solution of differential equation of (x+2y^3)dy = ydx is :

Answer»

`x = y^3 = cy`
`y = x^3 = cx `
`x^2 = y^2 =cxy`
None of these

Solution :The GIVEN differential equation can be WRITTEN as
`(DX)/(DY) - 1/y. x = 2y^2`
I.F. `e^(-int 1/y dy) = 1/y`
So solution is `x. 1/y = int 1/y 2y^2 .""dy= y^2+c`
So `x= y^3 + cy`


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