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Solution of differential equation of (x+2y^3)dy = ydx is : |
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Answer» `x = y^3 = cy` `(DX)/(DY) - 1/y. x = 2y^2` I.F. `e^(-int 1/y dy) = 1/y` So solution is `x. 1/y = int 1/y 2y^2 .""dy= y^2+c` So `x= y^3 + cy` |
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