1.

Solution of the differentiable equation (x+y−1x+y−2)dydx=(x+y+1x+y+2) such that, x=1 when y=1, is (where log is given with base ′e′)

Answer»

Solution of the differentiable equation (x+y1x+y2)dydx=(x+y+1x+y+2) such that, x=1 when y=1, is

(where log is given with base e)



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