1.

Solution of the differential equation : (3tan x=4 cot y-7)sin^(2)ydx-(4 tanx+7 cot y-5)cos^(2)xdy=0 is

Answer»

`(3)/(2)cot^(2)X-7 cotx+(7)/(2) TAN^(2)y-5 tany+4 cotx. tany=C`
`(3)/(2)tan^(2)x-7 tanx+(7)/(2)cot^(2)y-5 cot y+4tanx. coty=c`
`3 tan^(2)y-14cotx.tan^(2)y+7cot^(2)x-10tanycot^(2)x+8cotx. Tany+2c cot^(2)x tan^(2)y=0`.
`3 cot^(2)y-14cotx.cot^(2)y+7cot^(2)x+10coty tan^(2)x+8 tan x. coty=0`

Answer :B,C


Discussion

No Comment Found

Related InterviewSolutions