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Solution of the differential equation `x^(2)dy-2xydx=x^(3)y^(3)dx+x^(4)y^(2)dy` isA. `y=kx^(2)e^((x(2)y^(2))/2)`B. `y=ky^(2)e^((x^(2)y^(2))/2)`C. `y=k/(x^(2))e^((3x^(2)y^(2))/2`D. In `(y/(x^(2)))=((xy)^(2))/4+e^(c^(2))` |
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Answer» Correct Answer - A `(x^(2)dy-2xydx)/(x^(4))=(x^(3)y^(2)(ydx+xdy))/(x^(4))` `(d(y/(x^(2))))/(y/(x^(2)))=xyd(xy)` `implies` In `(y/(x^(2)))=((xy)^(2))/2+c` |
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