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Solve `0 lt | x-3| le 5` |
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Answer» `0 lt | x-3| le 5` `rArr -5 le x -3 lt 0 or 0 lt x -3 le 5` `rArr -2 le x lt 3 or 3 lt x le 8` `rArr x in [ -2 ,3 ) cup ( 3,8]` |
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