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Solve `|1+ (3)/(x)| gt 2` |
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Answer» `|1+ (3)/(x)| gt 2` or `-1le (x-3)/(x+1) le 1` `rArr (-4)/(x+1) le 0 " and " 0 le (x-3)/(x+1)+1` `rArr (-4)/(x+1) le 0 and 0 le (2x-2)/(x+1)` `rArr x gt -1 and { x lt -1 or x ge 1}` `rArr x ge 1` |
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