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Solve `(1)/(|x|-3) lt 1/2` |
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Answer» Correct Answer - ` x in (-oo ,5 ) cup (-3 , 3) cup (5,oo)` `(1)/(|x|-3)-1/2 lt 0` `or (2-|x|+3)/(|x|-3) lt 0 ` `or (|x|-5)/(|x|-3) gt 0 ` `rArr |x| gt 5 or |x| lt 3` ` rArr x lt 5 or x lt -5 or -3 lt x lt -3` `rArr x in (-oo , -5)cup(-3,3) cup (5,oo)` |
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