1.

Solve: 2(b + 3) + 13 = 27

Answer»

2(b + 3) + 13 = 27 

⇒ 2b + 6 + 13 = 27 (distributive law) 

⇒ 2b + 19 = 27 

⇒ 2b = 27 – 19 (∵+ 19 transposed and becomes – 19) 

⇒ 2b = 8 

⇒ b = 8/2 (∵ × 2 transposed and becomes ÷ 2) 

⇒ b = 4 

Check: 

Substitute b = 4 

LHS = 2(b + 3) + 13 

= 2(4 + 3) + 13 

= 2(7) + 13 

= 14 + 13 

= 27 = RHS 

Hence verified.



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