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Solve: 2(b + 3) + 13 = 27 |
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Answer» 2(b + 3) + 13 = 27 ⇒ 2b + 6 + 13 = 27 (distributive law) ⇒ 2b + 19 = 27 ⇒ 2b = 27 – 19 (∵+ 19 transposed and becomes – 19) ⇒ 2b = 8 ⇒ b = 8/2 (∵ × 2 transposed and becomes ÷ 2) ⇒ b = 4 Check: Substitute b = 4 LHS = 2(b + 3) + 13 = 2(4 + 3) + 13 = 2(7) + 13 = 14 + 13 = 27 = RHS Hence verified. |
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