1.

Solve: (2x+7)/5-(3x+11)/2=(2x+8)/3-5

Answer»

Given (2x+7)/5-(3x+11)/2 = (2x+8)-15

Now by taking L.C.M for 2 and 5 is 10

15(2(2x+7)-5(3x+11))/10 = (2x+8)/3-5

By transposing the above equation we can write as

33x-20x=123-70

Again by transposing

x=-53/53

x=-1



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