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Solve: (2x+7)/5-(3x+11)/2=(2x+8)/3-5 |
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Answer» Given (2x+7)/5-(3x+11)/2 = (2x+8)-15 Now by taking L.C.M for 2 and 5 is 10 15(2(2x+7)-5(3x+11))/10 = (2x+8)/3-5 By transposing the above equation we can write as 33x-20x=123-70 Again by transposing x=-53/53 x=-1 |
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