1.

Solve: `(3)/(x-2)gt2,x in R`

Answer» Correct Answer - `(2,(7)/(2))`
`(3)/(x-2)-2gt0 rArr (3-2x+4)/(x-2)gt0rArr(7-2x)/(x-2)gt0`
`rArr(7-2xlt0andx-2lt0) or(7-2x gt0and x-2gt0)`
`rArr (7lt2x and xlt2)or(7gt2x andxgt2)`
`rArr(xgt(7)/(2)andxlt2)or(xlt(7)/(2)andxgt2)`
`rArr 2ltxlt(7)/(2) rArr x in(2,(7)/(2))" "[xlt(7)/(2)andxgt2" cannot hold"]`


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