Solve `(3)/(x-2)lt1, " when "x inR`.

1.	Solve `(3)/(x-2)lt1, " when "x inR`.
Answer» Correct Answer - `x in (-oo,2)uu(5,oo)` `(3)/(x-2)-1lt0 rArr(3-x+2)/(x-2)lt0rArr(5-x)/(x-2)lt0`. `therefore (5-xlt0andx-2gt0)or(5-xgt0 andx-2lt0)` `rArr(xgt5 and xgt2)or(xlt5 and xlt2)` `rArr(xgt5 and xlt2)rArrx in(-oo,2)uu(5,oo)`.

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