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Solve 3x – 2 = 0 (mod 11) |
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Answer» Given 3x – 2 = 0 (mod 11) 3x – 2 = 11n (n may be any integer) 3x = 2 + 11n x = (11n + 2)/3 Substitute the value of n = 2, 5, 8, 11 … When n ≡ 2 ⇒ x = (22 + 2)/3 = 24/3 = 8 When n = 5 ⇒ x = (55 + 2)/3 = 57/3 = 19 When n = 8 ⇒ x = (88 + 2)/3 = 90/3 = 30 When n = 11 ⇒ x = (121 + 2)/3 = 123/3 = 41 ∴ The value of x is 8, 19, 30, 41 |
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