1.

Solve 3x – 2 = 0 (mod 11)

Answer»

Given 3x – 2 = 0 (mod 11) 

3x – 2 = 11n (n may be any integer) 

3x = 2 + 11n 

x = (11n + 2)/3 

Substitute the value of n = 2, 5, 8, 11 …

When n ≡ 2 ⇒ x = (22 + 2)/3 = 24/3 = 8

When n = 5 ⇒ x = (55 + 2)/3 = 57/3 = 19 

When n = 8 ⇒ x = (88 + 2)/3 = 90/3 = 30 

When n = 11 ⇒ x = (121 + 2)/3 = 123/3 = 41 

∴ The value of x is 8, 19, 30, 41



Discussion

No Comment Found