1.

Solve `|4-x|lt2`.

Answer» We have, `|x|ltaiff-altxlta`.
`therefore|4-x|lt2`
`iff-2lt4-xlt2`
`iff-2lt4-xand4-xlt2`
`iff -2-4-xand-xlt2-4`
`iff-6lt-xand-xlt-2`
`iff 6gt x andxgt2`.
`iff 2ltxlt6`.
`therefore` solution set `={x inR:2ltxlt6}=(2,6)`.


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