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    				| 1. | Solve `|4-x|lt2`. | 
| Answer» We have, `|x|ltaiff-altxlta`. `therefore|4-x|lt2` `iff-2lt4-xlt2` `iff-2lt4-xand4-xlt2` `iff -2-4-xand-xlt2-4` `iff-6lt-xand-xlt-2` `iff 6gt x andxgt2`. `iff 2ltxlt6`. `therefore` solution set `={x inR:2ltxlt6}=(2,6)`. | |