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Solve 41x + 53y = 135 and 53x + 41y = 147. |
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Answer» Given equations are 41x + 53y = 135 ….(1) and 53x + 41y = 147 ….(2) On adding equations (1) and (2) we get 94x + 94y = 282 implies x + y = 3 ….(3) On subtracting equation (2) from (1), we get -12x + 12y = - 12 implies x = y = 1 ....(4) Adding equations (3) and (4), we get 2x = 4 implies x = 2 Putting x = 2 in equation (3) 2 + y = 3 implies y = 1 Hence, the solution is `{:(x = 2),(y = 1):}}`. |
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