1.

Solve 41x + 53y = 135 and 53x + 41y = 147.

Answer» Given equations are 41x + 53y = 135 ….(1)
and 53x + 41y = 147 ….(2)
On adding equations (1) and (2) we get
94x + 94y = 282
implies x + y = 3 ….(3)

On subtracting equation (2) from (1), we get
-12x + 12y = - 12
implies x = y = 1 ....(4)
Adding equations (3) and (4), we get
2x = 4 implies x = 2
Putting x = 2 in equation (3)
2 + y = 3 implies y = 1
Hence, the solution is `{:(x = 2),(y = 1):}}`.


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