1.

Solve: `|5-2x|le3,x in R`

Answer» Correct Answer - `[1,4]`
`"Using" |x|leaiff-alexlea`, we get
`|5-2x|le3 rArr-3le5-2x le 3`
`rArr -3 le5-2x and 5-2xle3`
`rArr 2xle8 and2xge2 rArrxle4 xge1`
`rArr 1 le xle4 rArrx in[1,4]`.


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