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Solve [[a+x,a-x,a-x],[a-x,a+x,a-x],[a-x,a-x,a+x]]=0

Answer»

SOLUTION :`[[a+x,a-x,a-x],[a-x,a+x,a-x],[a-x,a-x,a+x]]`
or`[[3a-x,a-x,a-x],[3a-x,a+x,a-x],[3a-x,a-x,a+x]]=0`
`(C_1=C_1+C_2+C_3)`
`(3a-x)[[1,a-x,a-x],[1,a+x,a-x],[1,a-x,a+x]]=0`
or, `(3a-x)[[1,a-x,a-x],[0,+2X,0],[0,-2x,+2x]]=0`
`(R_2~~R_2-R_1,R_3~~R_3-R_2)`
or, `(3x-x)XX1[[2x,0],[-2x,2x]]=0`
or, `(3a-x)(4x^2-0)=0`
`therefore` x=0, x=3a


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