InterviewSolution
Saved Bookmarks
| 1. |
Solve [[a+x,a-x,a-x],[a-x,a+x,a-x],[a-x,a-x,a+x]]=0 |
|
Answer» SOLUTION :`[[a+x,a-x,a-x],[a-x,a+x,a-x],[a-x,a-x,a+x]]` or`[[3a-x,a-x,a-x],[3a-x,a+x,a-x],[3a-x,a-x,a+x]]=0` `(C_1=C_1+C_2+C_3)` `(3a-x)[[1,a-x,a-x],[1,a+x,a-x],[1,a-x,a+x]]=0` or, `(3a-x)[[1,a-x,a-x],[0,+2X,0],[0,-2x,+2x]]=0` `(R_2~~R_2-R_1,R_3~~R_3-R_2)` or, `(3x-x)XX1[[2x,0],[-2x,2x]]=0` or, `(3a-x)(4x^2-0)=0` `therefore` x=0, x=3a |
|