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))Solve any four of the following sub-questions.If the class mark is 10 and class width is 6, then find the class. |
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Answer» Let lower term of class be X and upper term be Y class mark = X + Y/ 210 = X + Y/220 = X + Y .... (1) class width = Y - X 6 = Y - X .... (2) On subtracting equation (2) from (1) 20 - 6 = X + Y - Y + X14 = 2X X = 14/2 X = 7 = lower limit on putting X in equation (2) 6 = Y - X6 = Y - 7Y = 7 + 6 = 13 = upper limit Ans. Class = 7 - 13 |
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