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Solve as directed : 2(3x-1) lt 7x + 1 lt 3 (2x +1) for real values. |
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Answer» SOLUTION :2(3x-1) `lt` 7x + 1 `lt` 3 (2x +1) `6X-2 lt 7x +1 lt 6x + 3` ` -2 lt x+1 lt 3 `rArr -3 lt x lt 2` If x `in` R the solution set is S = { x:x `in` R and `-3 lt x lt 2`} {-3,2} |
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