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Solve by componendo dividendo method |
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Answer» `((3x-4)^3-(x+1)^3)/((3x-4)^3+(x+1)^3) = 61/89` Using componendo and dividendo both sides, `((3x-4)^3-(x+1)^3+(3x-4)^3+(x+1)^3)/((3x-4)^3-(x+1)^3-(3x-4)^3-(x+1)^3) = (61+189)/(61-189)` `=>(2(3x-4)^3)/(-2(x+1)^3) = -250/128` `=>(3x-4)^3/(x+1)^3 = 125/64` `=>((3x-4)/(x+1))^3 = (5/4)^3` `=>(3x-4)/(x+1) = 5/4` `=>12x-16 = 5x+5` `=>7x = 21=> x = 3` |
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