1.

Solve byfactorization: `4x^2+4b x-(a^2-b^2)=0`

Answer» Correct Answer - `x=(-(b+a))/(2)" or "x=((a+b))/(2)`
`4x^(2)+4bx+(b^(2)-a^(2))=0`
`implies4x^(2)+2(b+a)x+2(b-a)x+(b^(2)-a^(2))=0`
`implies2x[2x+(b+a)]+(b-a)[2x+(b+a)]=0`
`implies[2x+(b+a)][2x+(b-a)]=0`
`impliesx=(-(b+a))/(2)" or "x=(a-b)/(0).`


Discussion

No Comment Found

Related InterviewSolutions