Solve : (dy/dx) - y tan x = - y sec2 x – InterviewSolution

1.

Solve : (dy/dx) - y tan x = - y sec2 x

Answer»

(dy/dx) - y.tan x = - y sec² x

(dy/dx) + y sec²x - y tan x = 0

(dy/dx) + (sec²x - tan x)y = 0

(dy/dx) = -(sec² x - tan x)y

(dy/y) = (tan x - sec²x)dx

Integrating both sides,

∫dy/dx = ∫(tan x - sec² x) dx

log y = log|sec x| - tan x + c

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