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Solve each of the following Cryptarithms: |
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Answer» Firstly let us solve for unit’s place, 7 + B = A And for ten’s place, 3 + A = 9 Which means that A = 6 and B = -1 which is not possible. So, there should be one carry in ten’s place which means 7 + B >9 3 +A +1 = 9 A = 9-1-3 = 5 For unit’s place subtracting 10 as one carry is given to ten’s place, 7 + B – 10 = 5 B = 5+10-7 = 8 ∴A = 5 and B = 8 |
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