1.

Solve each of the following system of inequations in R 3x – 1 ≥ 5, x + 2 > –1

Answer»

Given,

3x – 1 ≥ 5 and x + 2 > –1 

Let us consider the first inequality. 

3x – 1 ≥ 5 

⇒ 3x – 1 + 1 ≥ 5 + 1 

⇒ 3x ≥ 6

⇒ \(\frac{3x}{3}\) ≥ \(\frac{6}{3}\)

⇒ x ≥ 2 

∴ x ∈ (2, ∞) ...(1) 

Now,

Let us consider the second inequality. 

x + 2 > –1 

⇒ x + 2 – 2 > –1 – 2 

⇒ x > –3 

∴ x ∈ (–3, ∞) ...(2) 

From (1) and (2), we get 

x ∈ (2, ∞) ∩ (–3, ∞) 

∴ x ∈ (2, ∞) 

Thus, 

The solution of the given system of inequations is (2, ∞).



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