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Solve each of the following system of inequations in R2(x – 6) < 3x – 7, 11 – 2x < 6 – x |
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Answer» Given, 2(x – 6) < 3x – 7 and 11 – 2x < 6 – x Let us consider the first inequality. 2(x – 6) < 3x – 7 ⇒ 2x – 12 < 3x – 7 ⇒ 2x – 12 + 12 < 3x – 7 + 12 ⇒ 2x < 3x + 5 ⇒ 3x + 5 > 2x ⇒ 3x + 5 – 5 > 2x – 5 ⇒ 3x > 2x – 5 ⇒ 3x – 2x > 2x – 5 – 2x ⇒ x > –5 ∴ x ∈ (–5, ∞) ...(1) Now, Let us consider the second inequality. 11 – 2x < 6 – x ⇒ 11 – 2x – 11 < 6 – x – 11 ⇒ –2x < –x – 5 ⇒ –x – 5 > –2x ⇒ –x – 5 + 5 > –2x + 5 ⇒ –x > –2x + 5 ⇒ –x + 2x > –2x + 5 + 2x ⇒ x > 5 ∴ x ∈ (5, ∞) ...(2) From (1) and (2), we get x ∈ (–5, ∞) ∩ (5, ∞) ∴ x ∈ (5, ∞) Thus, The solution of the given system of inequations is (5, ∞). |
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