1.

Solve each of the following system of inequations in R0 < \(\frac{-x}{2}\) < 30 < -x/2 < 3

Answer»

Given,

0 < -x/2 < 3

The above inequality can be split into two inequalities.

0 <\(-\frac{x}{2}\) and \(-\frac{x}{2}\) < 3

Let us consider the first inequality.

 0 <\(-\frac{x}{2}\) 

⇒ 0\(\times\)2 < \(-\frac{x}{2}\)\(\times\)2

⇒ 0 < –x 

⇒ –x > 0 

⇒ x < 0 

∴ x ∈ (–∞, 0) ....(1) 

Now,

Let us consider the second inequality.

\(-\frac{x}{2}\) < 3

⇒ \(-\frac{x}{2}\) \(\times\) 2 < 3 \(\times\)2

⇒ –x < 6 

⇒ x > –6 

∴ x ∈ (–6, ∞) ...(2) 

From (1) and (2), we get 

x ∈ (–∞, 0) ∩ (–6, ∞) 

∴ x ∈ (–6, 0) 

Thus, 

The solution of the given system of inequations is (–6, 0).



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