Solve for x and y: 2x – y + 3 = 0, 3x – 7y + 10 = 0

1.	Solve for x and y: 2x – y + 3 = 0, 3x – 7y + 10 = 0
Answer» The given system of equation is: 2x – y + 3 = 0…….(i) 3x – 7y + 10 = 0 ……(ii) From (i), write y in terms of x to get y=2x + 3 Substituting y = 2x + 3 in (ii), we get 3x – 7(2x + 3) + 10 = 0 3x – 14x – 21 + 10 = 0 -7x = 21 – 10 = 11 x = – 11/7 Now substituting x = – 11/7 in (i), we have – 22/7 – y + 3 = 0 y = 3 - 22/7 = -1/7 Hence, x = – 11/ 7 and y = – 1/ 7 .

Answer»

The given system of equation is:

2x – y + 3 = 0…….(i)

3x – 7y + 10 = 0 ……(ii)

From (i), write y in terms of x to get

y=2x + 3

Substituting y = 2x + 3 in (ii), we get

3x – 7(2x + 3) + 10 = 0

3x – 14x – 21 + 10 = 0

-7x = 21 – 10 = 11

x = – 11/7

Now substituting x = – 11/7 in (i), we have

– 22/7 – y + 3 = 0

y = 3 - 22/7 = -1/7

Hence, x = – 11/ 7 and y = – 1/ 7 .

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