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Solve for x and y : 2x + y = 7, 4x – 3y + 1 = 0 |
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Answer» 2x + y = 7 ... (1) And 4x – 3y + 1 = 0 ⇒ 4x – 3y = –1 ... (2) Now, multiplying equation (1) by 2, we get 4x + 2y = 14 ... (3) Now subtracting equation (2) from (3), we get 4x + 2y – (4x – 3y) = 14 – (–1) ⇒ 5y = 15 ⇒ y = 3. Now, putting y = 3 in equation (1), we get 2x + 3 = 7 ⇒ 2x = 7 – 3 = 4 ⇒ x = 4/2 = 2. Hence, the solution of given system of equations is x = 2 and y = 3. |
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