1.

Solve for x and y : 2x + y = 7, 4x – 3y + 1 = 0

Answer»

2x + y = 7          ... (1) 

And 4x – 3y + 1 = 0 

⇒ 4x – 3y = –1     ... (2) 

Now, multiplying equation (1) by 2, we get 

4x + 2y = 14 ... (3) 

Now subtracting equation (2) from (3), we get 

4x + 2y – (4x – 3y) = 14 – (–1) 

⇒ 5y = 15 ⇒ y = 3. 

Now, putting y = 3 in equation (1), we get 

2x + 3 = 7 

⇒ 2x = 7 – 3 = 4 

⇒ x = 4/2 = 2. 

Hence, the solution of given system of equations is x = 2 and y = 3.



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