Solve for x and y:\(\frac{3}x+\frac{6}y=7\),\(\frac{9}x+\frac{3}y=11\)

1.	Solve for x and y:\(\frac{3}x+\frac{6}y=7\),\(\frac{9}x+\frac{3}y=11\)
Answer» The given equations can be written as \(\frac{3}x+\frac{6}y=7\)...........(i) \(\frac{9}x+\frac{3}y=11\)......(ii) Multiplying (i) by 3 and subtracting (ii) from it, we get 18/y - 3/y = 21 – 11 ⇒ 15/y = 10 ⇒ y = 15/10 = 3/2 Substituting y = 3/2 in (i), we have 3/x + 6×2/3 = 7 ⇒ 3/x = 7 – 4 = 3 Hence, x = 1 and y = 3/2.

Answer»

The given equations can be written as

\(\frac{3}x+\frac{6}y=7\)...........(i)

\(\frac{9}x+\frac{3}y=11\)......(ii)

Multiplying (i) by 3 and subtracting (ii) from it, we get

18/y - 3/y = 21 – 11

⇒ 15/y = 10

⇒ y = 15/10 = 3/2

Substituting y = 3/2 in (i), we have

3/x + 6×2/3 = 7

⇒ 3/x = 7 – 4 = 3

Hence, x = 1 and y = 3/2.

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