Solve for x and y: x – y = 3, x/3 + y/2 = 6

1.	Solve for x and y: x – y = 3, x/3 + y/2 = 6
Answer» The given system of equations is x – y = 3 …..(i) x/3 + y/2 = 6 ……(ii) From (i), write y in terms of x to get y = x – 3 Substituting y = x – 3 in (ii), we get x/3 + x −3/ 2 = 6 ⇒2x + 3(x – 3) = 36 ⇒2x + 3x – 9 = 36 ⇒x = 45/ 5 = 9 Now, substituting x = 9 in (i), we have 9 – y = 3 ⇒y = 9 – 3 = 6 Hence, x = 9 and y = 6.

Answer»

The given system of equations is

x – y = 3 …..(i)

x/3 + y/2 = 6 ……(ii)

From (i), write y in terms of x to get

y = x – 3

Substituting y = x – 3 in (ii), we get

x/3 + x −3/ 2 = 6

⇒2x + 3(x – 3) = 36

⇒2x + 3x – 9 = 36

⇒x = 45/ 5 = 9

Now, substituting x = 9 in (i), we have

9 – y = 3

⇒y = 9 – 3 = 6

Hence, x = 9 and y = 6.

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