solve for x and y3x-5y=42y+7=9x

1.	solve for x and y3x-5y=42y+7=9x
Answer» There are two equations provided here. 3x – 5y – 4 = 0 3x -5y = 4 ……. (1). 9x = 2y + 7 9x -2y = 7 ……(2). We have to solve for x and y in the given equations by the elimination method Now only considering equations (1) and (2) 3x – 5y = 4………(1) 9x – 2y = 7 ……(2) On multiplying eq. (1) by 3, we get…. 3 (3x – 5y = 4) 9x – 15y = 12…… (3). Now we can easily subtract (2) and (3) to get….. 9x – 2y = 7 – 9x – 15y = 12. – +13 y = -5 Or we get 13 y = -5 or y = -5/13. Now we substitute the value of Y = -5/13 in equation (1) we get the value of x. 3x – 5(-5/13) = 4 3x +25/13 = 4 39x + 25 = 52 Or 39x = 52 – 25 39x = 27 Or x = 27/39 = 9 / 13 So x = 9/13 and y = -5/13. x = 9/13 and y = -5/13

Answer»

There are two equations provided here.

3x – 5y – 4 = 0

3x -5y = 4 ……. (1).

9x = 2y + 7

9x -2y = 7 ……(2).

We have to solve for x and y in the given equations by the elimination method

Now only considering equations (1) and (2)

3x – 5y = 4………(1)

9x – 2y = 7 ……(2)

On multiplying eq. (1) by 3, we get….

3 (3x – 5y = 4)

9x – 15y = 12…… (3).

Now we can easily subtract (2) and (3) to get…..

9x – 2y = 7

– 9x – 15y = 12.

– +13 y = -5

Or we get 13 y = -5 or y = -5/13.

Now we substitute the value of Y = -5/13 in equation (1) we get the value of x.

3x – 5(-5/13) = 4

3x +25/13 = 4

39x + 25 = 52

Or 39x = 52 – 25

39x = 27

Or x = 27/39 = 9 / 13

So x = 9/13 and y = -5/13.

x = 9/13 and y = -5/13

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