1.

Solve for x:tan−1(x−1)+tan−1x+tan−1(x+1)=tan−13x. OR Prove that : (6x−8x31−12x2)−tan−1(4x1−4x2)=tan−12x;|2x|<1√3.

Answer»

Solve for x:tan1(x1)+tan1x+tan1(x+1)=tan13x.

OR

Prove that : (6x8x3112x2)tan1(4x14x2)=tan12x;|2x|<13.



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