1.

Solve :(i)  y + 3 = 10(ii) 6 = z +2 

Answer»

(i) y + 3 = 10

Transposing 3 to R.H.S, we obtain

y = 10 − 3 = 7

(ii) 6 = z + 2

Transposing 2 to L.H.S, we obtain

6 − 2 = z

z = 4



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